help with xsl if statement

Question

I am trying to change the icon for the "Link to Document" on the searchResult.aspx page. I added following to the xslt of the result but then the result webpart never renders meaning the code is broke. I tried to follow SP2007 article (http://msdn.microsoft.com/en-us/library/cc789805(v=office.12).aspx) but my environment is SP 2010. Please suggest.

<xsl:choose> 
<xsl:when test="contenttype='LegalLinkedDocument'"> 
<img align="absmiddle" src="_layouts/images/legalIcon.gif" border="0" alt="{imageurl/@imageurldescription}" />
</xsl:when>
<xsl:otherwise>
 <img align="absmiddle" src="{imageurl}" border="0" alt="{imageurl/@imageurldescription}" /> </xsl:otherwise>
</xsl:choose>

Answer 1

you can use @ContentType as well.

Answer 2

You need to close the nodes. You never close out your xsl:if statement.

http://www.w3schools.com/xsl/xsl_if.asp

Just like XML, every tag needs a beginning and end.

I'm not sure exactly what you're doing here, but I think an xsl:choose statement might be more appropriate to handle the else portion of the if...else statement via xsl:otherwise.

http://www.w3schools.com/xsl/xsl_choose.asp

Answer 3

Try putting the contenttype value into a variable before using it in the condition

<xsl:variable name="contenttype" select="contenttype"/>
<xsl:choose>  
  <xsl:when test="$contenttype = 'LegalLinkedDocument'">  
    <img align="absmiddle" src="_layouts/images/legalIcon.gif" border="0" alt="{imageurl/@imageurldescription}" /> 
  </xsl:when> 
  <xsl:otherwise> 
    <img align="absmiddle" src="{imageurl}" border="0" alt="{imageurl/@imageurldescription}" />
  </xsl:otherwise> 
</xsl:choose> 

Answer 4

I followed this link and then compared:

<xsl:when test="ctype='LegalLinkedDocument'"> 

Now it's all good.

@Per Jakobsen: Your solution did not work for me.