I have a relatively simple scenario which I am trying to implement in Power Apps, but can't seem to make it work.

I have 2 drop downs which source values will be from a SharePoint list with 2 columns Region and Department. Both these columns are Choice type columns

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Department dropdown will depend on Region selected

  1. Region dropdown Items property


  2. Department dropdown Items property

    Filter([@MySharePointList], Region.Value = ddlRegion.Selected.Value).Department

I think it filters correctly, however they are Records. As a result, the dropdown has items but are shown as empty items.

How do I retrieve the actual value of the Department for this dropdown?

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  • Can you confirm if you using dropdown or combobox control for department and region? Is this a standalone canvas app or Power Apps customized list form? Apr 25, 2023 at 7:05
  • Standalone canvas app. Dropdown control for both. Thanks. Apr 25, 2023 at 7:19
  • Check my answer given below Apr 25, 2023 at 7:36

1 Answer 1


Use below formula for Department drop down Items property:

Distinct(Filter([@MySharePointList], Region.Value = ddlRegion.Selected.Value), Department.Value)

SharePoint list:

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Power Apps output:

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  • Thanks it works. Funny, it seems that we need to use Distinct outside Filter for this case to work. For example using Filter([@MySharePointList], Region.Value = ddlRegion.Selected.Value).Department.Value does not work. Was wondering if you know why? Apr 25, 2023 at 7:50
  • items property of drop down control expects a table/array input. So, we are creating array of departments using distinct values from Department.Value. Apr 25, 2023 at 7:53
  • Understand, however I think Filter return a table as well? A table of 'Records' in my case (as per screenshot). Hence shouldn't it work with .Department.Value on Filter? Or am I missing something Apr 25, 2023 at 8:04
  • Value property of drop down control works only with simple values such as text, number, dates, etc. While Filter([@MySharePointList], Region.Value = ddlRegion.Selected.Value).Department returns nested/complex objects which are not supported. When you try to use it, you will get warning/error in formula bar. Apr 25, 2023 at 8:20
  • Understood that .Department are complex objects. But was wondering why we can't use .Value directly on Department, example:Filter([@MySharePointList], Region.Value = ddlRegion.Selected.Value).Department.Value. This gives a syntax error. Apr 25, 2023 at 9:56

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