I have the following script :

$site = new-object Microsoft.SharePoint.SPSite("http://TEST123")
$web = $site.OpenWeb()
$field = $ct.Fields.GetFieldByInternalName("AddTESTColumn")                            
$ct.FieldLinks[$field.id].DisplayName ="AddTESTColumn"     

I have used the above to update the display name of a column that is associated to CT.

But now I want to update a choice field column so will be adding a new choice "away" to the current choices tried to use the choices.add but keep getting error message

I used the following :

$site = Get-SPSite -Identity "http://TEST123"

$web = $site.RootWeb
$field = 

and get the following message:

You cannot call a method on a null-valued expression.

the issue is with $field = $web.Fields["AddTESTColumn"]; as its not recognising the field name even though it exist. I have used both internal and display name, same issue.

  • please add the code you tried for adding the choice. – harshal gite Sep 6 '19 at 12:45
  • what's the error message that you are getting ? – Gautam Sheth Sep 6 '19 at 12:48
  • Your code looks fine. Please remember that the field names are case sensitive. – Mike2500 Sep 6 '19 at 13:06
  • Yes made sure of that, just tested it with another choice field in the content type works ok for that something with that column its just not liking the name – John Smith Sep 6 '19 at 13:11
  • Just to confirm, if you run the following, you can find your column, and the Title matches what you're using in the script? $web.fields | select title,internalname | sort title | ft – Mike2500 Sep 6 '19 at 13:19

If it is a Site Column then your code is fine.

$site = Get-SPSite -Identity "http://TEST123"    
$web = $site.RootWeb
$field = $web.Fields["SiteColumnInternalName"];

If it is a list column and not a site column, then try the code below.

$site = Get-SPSite -Identity "http://TEST123"    
$web = $site.RootWeb
$List = $web.Lists["ListName"]
$field = $list.Fields.GetField("ColumnInternalName");

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