2

I have a function that spits out the Parent navigation node along with the Child navigation node. This function:

function printNodesInfo(nodes){
nodes.get_data().forEach(function(node){
    var childNodes = node.get_children();
   console.log(String.format('Parent Title: {0} | Url: {1}',node.get_title(), '<a href='+node.get_url()+'>View</a>'));

    childNodes.get_data().forEach(function(childNode){
       console.log(String.format('- Child Title: {0} | Url: {1}',childNode.get_title(),childNode.get_url())); 
    });
}); 

}

spits out this in console

Parent Title: Documents | Url: hidden

  • Child Title: Summit | Url: hidden

Parent Title: Lists | Url: hidden

  • Child Title: List 1 | Url: hidden

I want to display the results in a div on one of my html files. Each time I try

document.getElementById('my-id').innerHTML += (String.format('Parent Title: {0} | Url: {1}',node.get_title(), '<a href='+node.get_url()+'>View</a>'));
document.getElementById('my-id2').innerHTML += (String.format('- Child Title: {0} | Url: {1}',childNode.get_title(),childNode.get_url())); 

I get all my navigation nodes but the child node sits at the bottom of all my parent navigation items. How can I display them in the same fashion as they get displayed in my console.log().

Thanks in advanced.

2

Figured it out.

The solution was to target the same div, not two different divs inside of the document.getElementById('').innerHTML.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.