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i have link button inside gridview. can some one help me to form proper URL for this

  <asp:TemplateField HeaderText="View" >
<ItemTemplate><asp:LinkButton runat="server" ID="lnkView" OnClientClick="OpenDialog('/SitePages/View%20Booking.aspx?','','');return false;" ><%#Eval("Booking Name") %></asp:LinkButton>

                                     </ItemTemplate>

                                   </asp:TemplateField>

if i use above, than popup opens fine on link button click but if append parameter as shown below, it throws error on load itself.

<asp:LinkButton runat="server" ID="lnkView" OnClientClick="OpenDialog('/SitePages/View%20Booking.aspx?BID="+ Eval("ID")+"','','');return false;" ><%#Eval("Booking Name") %></asp:LinkButton>

can some one help to form proper URL?

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use escape entities like \"

or you don't need to use quotes for the query string values it will work without that also

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