Get Url of List, with all items

Question

I created a document library by code, and I need to return the URL of the All Items page.

I tried this, but its not what I am looking for

 SPList oSPList = oSPWeb.Lists.TryGetList(DocumentLibraryName);
                        if (oSPList == null)
                        {
                            Guid ID = oSPWeb.Lists.Add(DocumentLibraryName, DocumentLibraryName + System.DateTime.Now.ToString(), SPListTemplateType.DocumentLibrary);
                            oSPList = oSPWeb.Lists[ID];
                            DocumentLibraryLink = oSPList.DefaultViewUrl;

Answer 1

I'm guessing that you want the complete url to the Default view and not just the server relative url to the view. If that is true, you can do the following to get the easily get the full url.

DocumentLibraryLink = SPUtility.ConcatUrls(oSPWeb.Url, oSPList.DefaultView.Url);

The result is something like this

http://servername/sitecollection/site/lists/listname/defaultpagename.aspx

If the view is not the default view, you can use this. ViewName is the Display Name for the view.

DocumentLibraryLink = SPUtility.ConcatUrls(oSPWeb.Url, oSPList.Views[ViewName].Url);

This will give the url even if it is located in the FORMS folder.

http://servername/sitecollection/site/lists/listname/forms/viewname.aspx

Answer 2

Try

SPUrlUtility.CombineUrl(oSPWeb.Site.Url,oSPList.DefaultViewUrl);