How to display lookup additional field in display form?

Question

I have two lists: Projects and Tasks

In the Tasks list, I have created a lookup field titled ProjectID which targets ID filed from the Projects list. Also, I have set for this field to display an additional field ProjectID: Title. So, when I view the tasks I see the values for the particular project ID and Title.

However, on the display form for the Tasks I can only see the ProjectID field. I've modified the display form to hide the default display web part and created a custom one in order to be able to customize the fields presentation. Now I have two problems:

1. ProjectID field is displaying the whole <a... /> tag instead of just the value for the ID (which should act as a link to the related project item)
2. I can't find a way to display the ProjectID:Title field at all. I tried:
   <td width="400px" valign="top" class="ms-formbody">
    <xsl:value-of select="@ProjectID_x003a_Title" />
</td>
   but the field is just blank.

Is there a way to be able to show lookup additional field in the display form?
Thanks.

Answer 1

[There was a not useful answer]

UPDATE: OK, I understand the problem now. In my case the field is present in the section (I've removed other fields for simplicity):

<DataFields>@MultiLookupTest_x003a_TestField,MultiLookupTest:TestField;</DataFields>

And then you can render it just in the same manner as others but you need to use a part of identifier:

<xsl:value-of select="@MultiLookupTest_x003a_TestField"/>

Unfortunately you'll get your projected value in the same form of tag. But here there's an advice:

I found another solution by selecting the cell and clicking "format as label".

Maybe it hepls you.

Answer 2

You can set "readonly" property of your additional field to FALSE (by code or sharepoint manager, for example). Then this field will be presented in display form.